- Joined
- Apr 21, 2005
- Sythe Gold
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0.96L eth + 1.1122L h20
757.44g eth + 1112.2g h20
roughly
Nope.
0.96L eth + 1.1122L h20
757.44g eth + 1112.2g h20
roughly
0.96L eth + 1.1122L h20
757.44g eth + 1112.2g h20
roughly
the issue a lot of you are having is assuming that volumes are perfectly additive for liquids. this is true if liquid1 = liquid2 but not if they're different. see this for more
Repeating the same wrong answer a third time doesn't make it right
1.25L of Ethanol
0.75L of Water
#Death
0.78924a + 0.9982b = .91384 * 2000 //Density of water/alcohol mixture @ 50% ABV is 0.91384g/ml
a + b = 2000 //Total volume must be 2000 mL
Let's use Gauss' elimination to solve this system
1 1 2000.00
0,78924 0,9982 1827.68 //L2 -> L2 - 0.78924 * L1
~
1 1 2000
0 0.20896 249.2
0.20896b = 249.2
b = 249.2/0.20896
b = 1192,573 ml
a + b = 2000
a + 1192.573 = 2000
a = 807.427
guys stop posting, it's meanless, I got the right answer.
Jim hired me to be his assistant
needs more than 2L of total starting fluid to get 2L of fluid at the end due to thermodynamics I believe as it releases some heat and contracts, will check later and do some work on it, have some class sht to get dun b4 thanksgiving break >_<
ye i know but i was fucking bored of trying to find the answer so i came up with a not-really-valid answer and influenced other people to quit trying to answer by telling them I had the correct answer
Jim is working in a lab at 293.15 K. He has a solution of pure ethanol but he wants to make a 2L solution of 50% ABV alcohol for drinking. What mass of water and ethanol should he combine?
Fuck yeah, party at Jim's in the freezing cold! Serving the delightful beverage of 50% water/ethanol!
topkek retard not knowing that 293K is 20 Celsius

