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solution is:

1000g of water

789.24g of ethanol

what do i win?
 
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How come I didn't get a response on my correct answer? Getting the pitchfork as we speak
 
The answer is definetly 1000g of water and 789g of pure ethanol

because 1000ml of water mixed with 1000ml of ethanol = 50% ABV.

1000ml of water = 1000g of water (Water is 1g/ml)

1000ml of ethanol = 789,24g of ethanol (Ethanol is 0,78924g/ml)

thus making the final solution: total mass of 1789.24g and 50% ABV
 
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How come I didn't get a response on my correct answer? Getting the pitchfork as we speak

Your answer was incorrect even if I had asked for volumes.

The answer is definetly 1000g of water and 789g of pure ethanol

because 1000ml of water mixed with 1000ml of ethanol = 50% ABV.

1000ml of water = 1000g of water (Water is 1g/ml)

1000ml of ethanol = 789,24g of ethanol (Ethanol is 0,78924g/ml)

thus making the final solution: total mass of 1789.24g and 50% ABV


Neither the working nor the answer is correct.

The only correct thing you've posted so far is that 789.24 g of pure ethanol at 293.15 K consumes 1.00 L of volume.
 
Your answer was incorrect even if I had asked for volumes.




Neither the working nor the answer is correct.

The only correct thing you've posted so far is that 789.24 g of pure ethanol at 293.15 K consumes 1.00 L of volume.

Last try...

water mixed with alcohol = 1.92 volume unit

so to have 2L of 50%abv you would need...

1041,67 ml of water -> 1041,67g of water

and

1041,67 ml of alcohol -> 822.128g of alcohol

solution total mass: 1863.8g
 
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o god chemistry, have not done this in a good 6 years


well guessing its 1L water 1L ethanol ... but mass grr



m_ethanol = 789.45 grams

m_water = 998.2071 grams


using densities given by le wikipedia (10/10 source) at 20 degrees C, even if liquids densities change by temperature, as long as temperature stays the same and 50% ABV does mean 1L water 1L ethanol to give a total of 2L solution, then just multiplying 1000 cm3 (1L) by the densities given in g/cm3 should give the mass of the 1L of water/ethanol, which one looking at currently. I know that water isn't exactly 1 g/cm3 and assuming 1 atm of pressure, since because I assume the person to be drinking on Earth above ground.


Been a long time since I've taken chem, so go easy on me if wrong lol. Also I'm unsure if I need to do any of those chemical formulas to check the output chemicals, except I believe ethanol is the hydrated of ethene and more water shouldnt change the chemical
 
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Jim is working in a lab at 293.15 K. He has a solution of pure ethanol but he wants to make a 2L solution of 50% ABV alcohol for drinking. What mass of water and ethanol should he combine?
0.96L eth + 1.1122L h20
757.44g eth + 1112.2g h20
roughly


the issue a lot of you are having is assuming that volumes are perfectly additive for liquids. this is true if liquid1 = liquid2 but not if they're different. see this for more
 
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