- Joined
- Apr 21, 2005
- Sythe Gold
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50% ethanol = 100%
50% water = 50%
1/2 = 50
i win
I'm a fuckin scholar
Repeating the same wrong answer a third time doesn't make it right
50% ethanol = 100%
50% water = 50%
1/2 = 50
i win
I'm a fuckin scholar
solution is:
1000g of water
789.24g of ethanol
what do i win?
100 proof is defined as exactly 50% ABV by modern definition, but that wasn't the question.
uk standards is 57.06%
uk standards is 57.06%
1042 g water 822 g ethanol
thx
How come I didn't get a response on my correct answer? Getting the pitchfork as we speak
The answer is definetly 1000g of water and 789g of pure ethanol
because 1000ml of water mixed with 1000ml of ethanol = 50% ABV.
1000ml of water = 1000g of water (Water is 1g/ml)
1000ml of ethanol = 789,24g of ethanol (Ethanol is 0,78924g/ml)
thus making the final solution: total mass of 1789.24g and 50% ABV
Your answer was incorrect even if I had asked for volumes.
Neither the working nor the answer is correct.
The only correct thing you've posted so far is that 789.24 g of pure ethanol at 293.15 K consumes 1.00 L of volume.
o god chemistry, have not done this in a good 6 years
well guessing its 1L water 1L ethanol ... but mass grr
Last try...
water mixed with alcohol = 1.92 volume unit
so to have 2L of 50%abv you would need...
1041,67 ml of water -> 1041,67g of water
and
1041,67 ml of alcohol -> 822.128g of alcohol
solution total mass: 1863.8g
Wrongm_ethanol = 789.45 grams
m_water = 998.2071 grams
using densities given by le wikipedia (10/10 source) at 20 degrees C, even if liquids densities change by temperature, as long as temperature stays the same and 50% ABV does mean 1L water 1L ethanol to give a total of 2L
0.96L eth + 1.1122L h20Jim is working in a lab at 293.15 K. He has a solution of pure ethanol but he wants to make a 2L solution of 50% ABV alcohol for drinking. What mass of water and ethanol should he combine?

