789.24 g of pure ethanol at 293.15 K consumes 1.00 L of volume.
789.24g ethanol + 1000g water = 1.9274 L 50% ABV solution at your temp
818.97g ethanol + 1037.7g water = 2.0 L 50% ABV solution at your temp
789.24 g of pure ethanol at 293.15 K consumes 1.00 L of volume.
Wrong1035 g water 818 g ethanol?
My last last try:
Code:0.78924a + 0.9982b = .91384 * 2000 //Density of water/alcohol mixture @ 50% ABV is 0.91384g/ml a + b = 2000 //Total volume must be 2000 mL Let's use Gauss' elimination to solve this system 1 1 2000.00 0,78924 0,9982 1827.68 //L2 -> L2 - 0.78924 * L1 ~ 1 1 2000 0 0.20896 249.2 0.20896b = 249.2 b = 249.2/0.20896 b = 1192,573 ml a + b = 2000 a + 1192.573 = 2000 a = 807.427
Jim needs to mix 1192,573ml of water with 807,427ml of alcohol
to get 2L of 50% ABV solution
needs more than 2L of total starting fluid to get 2L of fluid at the end due to thermodynamics I believe as it releases some heat and contracts, will check later and do some work on it, have some class sht to get dun b4 thanksgiving break >_<
This shouldn't be that difficult, I'll give it a show.
To start with we have pure ethanol: C2H6O
In order to make this in to 2L we need to add some classic H2O
C2H6O + H2O
By using Grant's Law of Conservation of Food as clearly stated in book 7, we can determine that ethanol has 3 letters and water has 2, as a result, we have a 3:2 molar mass ratio. However this is where many people go wrong, they typically forget to add the molar mass with the overall molarity of the ethanol solution. Which is ~46g.
So in 2L, we get a 3:2 ratio, with an added amount of 46g.
So we actually end up with 92g OVER 2L, in order to actually amount to 2L in the end.
So it becomes 40% of 2L + 46g of H2O PLUS 60% of 2L + 46g of ethanol.
That was a pain, but not incredibly difficult, got any more?
789.24g ethanol + 1000g water = 1.9274 L 50% ABV solution at your temp
818.97g ethanol + 1037.7g water = 2.0 L 50% ABV solution at your temp
Wrong answer but working partially correct. Mass is a conserved quantity unlike volume..
True that volume is not a conserved quantity and more is needed to start. Wrong in thinking that this is due to heat.
Is it due to the fact that some is give off as O2 or CO or something like that
the number of millilitres of pure ethanol present in 100 millilitres of solution at 20°C.
Wrong
Wrong working wrong answer
.
No. It's due to the geometry of the molecules. They become closer together when concentrations are around 1:1.
Nobody got the answer, you'd all fail miserably working at a distillery.
ABV (Alcohol by volume) is defined as
First, to clarify:
The density of pure ethanol at 293.15 K is 789.24 g/L.
The density of pure water at 293.15 K is 998.20 g/L.
Working at 293.15 K: If you take 789.24 g of ethanol and put it in a beaker, it will consume 1 L of volume. If you take 998.20 g of water and put it in a beaker it will consume 1L of volume. But when you combine them the final solution actually consumes less than 2 L of volume. This is a problem because the definition of ABV is (volume of ethanol)/(total volume of solution).
In fact the way to work this out is to do an experiment or use an empirical table drawn up by someone who already did the experiment. Simply add 1L of pure ethanol to a container then continue to fill with water until you reach a 2L volume. This is strictly 50% ABV.
Here was the answer:
1071.04 g water (1.07 L)
789.24 g ethanol (1.00 L)
Combined make a total of exactly 2.00 L. There is a 70 ml shrinkage of the volume due to the above mentioned effects.
Stay tuned for the next installment of Sythe Users: What Do They Know? Do They Know Things?? Lets Find Out!
significantly more fishy than ethanol and watertl;dr = tell me wut pussy tastes like

