Question, is that 0.999... repeating, as in never ending?
Question, is that 0.999... repeating, as in never ending?
Here's another more conventional way to think about it:
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yes, 0,9 followed by an infinite amount of 9.
that's why he is able to show that 0.9 = 1, if there isn't an infinite amount of 9s, it isn't equal to 1.
for example,
0,999 != 1
0.999 = X
10X = 9.99
10X - X = 9.99 - .999 = 8.991
9X = 8.991 => X = 0.999 != 1
So then how exactly can you claim the following (pardon my poor notation):
Y = 0.999...
10Y = 10 * (0.999...)
10Y = ...99990
While the basic principle makes sense, isn't that effectively giving infinity an endpoint, which you cannot do? That's saying that where the 0 now is, that was the end of the infinitely repeating 9s. How can there be an end to that?
So then how exactly can you claim the following (pardon my poor notation):
Y = 0.999...
10Y = 10 * (0.999...)
10Y = ...99990
While the basic principle makes sense, isn't that effectively giving infinity an endpoint, which you cannot do? That's saying that where the 0 now is, that was the end of the infinitely repeating 9s. How can there be an end to that?
y = ∞
y + 1 = ∞
y - ∞ = ∞
there.
edit: Y is infinity. Therefore Y is all numbers simultaneously.
There isn't a single scenario where ...999999 infinite 9's are generated unless they're in the decimals. If thats what you mean, then .9 repeated.
it doesn't equal -1, but -1.1 repeated.
you fail so bad, infinity is not all numbers simultaneously
if so you could say
∞ = 2
∞ = 4
∞ = -74
and then you could say that 2 = -74 = ∞
see how that doesn't work ?
You're right, it doesn't work. That's because infinity is a concept and doesn't exist in reality. Therefore it cannot be calculated logically.
Edit: The proof itself already uses that logic that you are professing against. It claims that ...999999 = -1
It does not work both ways because an infinite fraction is not an infinite number and is not comparable.
huh ... an infinite fraction is an infinite number ... it's 0,9 followed by an infinite amount of 9s.
the proof doesn't assert that infinity = -1 or 1,
it just uses algebra to get rid of the concept of infinity
X = 0.9999...
10X = 9.99999...
10X - X = 9.9999... - 0.99999....
9X = 9 => X = 1
Sorry sythe, I have a personal policy not to appropriately participate in anything Deathsnova has already marred with his presence. Therefore, I cannot answer your question with impeccable reasoning and excellent vocabulary :c
there is no leftmost position? otherwise we could also say 1-0.999... = 0.000...1
Y is a geometric serie of first term 9 and ratio 10.
10Y is a geometric serie of first term 90 and ratio 10.
Y = 9 * (1 - 10^n+1) / (1 - 10)
Y = 9 - 9*(10^n) / -9
Y = 9/-9 - 9(10^n)/-9
Y = -1 + 10^n
10Y = 90 * (1 - 10^n) / (1 - 10)
10Y = 90/-9 + 10(10^n)
10Y = -10 + 10(10^n)
Y - 9 = -1 + (10^n) - 9
Y - 9 = -10 + 10^n
Y - 9 = 10Y
-1 + 10^n - 9 = -10 + 10(10^n)
-9 = -10 + 10(10^n) + 1 - 10^n
-9 = -10 + (100^n) + 1 - 10^n
-9 = -9 + 10(10^n) - 10^n
-9 = -9 + 10^n * (10 - 1)
-9 = -9 + 10^n * 9
...
no more time to think this through, i'm probably close but so far away
Sorry sythe, I have a personal policy not to appropriately participate in anything Deathsnova has already marred with his presence. Therefore, I cannot answer your question with impeccable reasoning and excellent vocabulary :c
Not sure how you want to go about this,
in the above picture, Y and 10Y both are equal to infinity because this is a geometric series whos ratio is greater than 1
So then how exactly can you claim the following (pardon my poor notation):
Y = 0.999...
10Y = 10 * (0.999...)
10Y = ...99990
While the basic principle makes sense, isn't that effectively giving infinity an endpoint, which you cannot do? That's saying that where the 0 now is, that was the end of the infinitely repeating 9s. How can there be an end to that?
I already give you the sum notation to show you can construct these numbers.There isn't a single scenario where ...999999 infinite 9's are generated unless they're in the decimals. If thats what you mean, then .9 repeated.
You're right, it doesn't work. That's because infinity is a concept and doesn't exist in reality. Therefore it cannot be calculated logically.
Edit: The proof itself already uses that logic that you are professing against. It claims that ...999999 = -1
It does not work both ways because an infinite fraction is not an infinite number and is not comparable.
huh ... an infinite fraction is an infinite number ... it's 0,9 followed by an infinite amount of 9s.
the proof doesn't assert that infinity = -1 or 1,
it just uses algebra to get rid of the concept of infinity
X = 0.9999...
10X = 9.99999...
10X - X = 9.9999... - 0.99999....
9X = 9 => X = 1
And it arrives at the conclusion that -1 = 9999999 proving conventional mathematics is inadequate at handling infinite concepts. I'll agree that even infinite decimals are infinite since using the same mathematics, one is still forced to round the number to arrive at a solution, a technically incorrect one at that.
Edit: Even the original problem proposes 9.99999... - .99999... = 9. This is incorrect. This problem could never be solved because it would be subtracting infinitely meaning it would never arrive at a solution. Just in the sense that ∞ - ∞ = ∞. Infinity will always be infinity no matter what you give or take from it.
Like the idea that parallel lines cross at infinity, by adding 1 your one shoots off to the start of the set of 0's. It lives at infinity, but it doesn't disappear. If it could disappear at some point then it wouldn't be able to change all the 9's into 0's.
Not going to check your working but the last line is 0 = 10^n. There's no n in the real numbers which gives 0. But this ties into what I'll say below.
Opting out. That's a valid strategy
No, when we have an infinite series that does not converge we do not say it's equal to infinity. We say it does not converge. There is a very important difference. In one case we are treating infinity as a concept and in the other we are treating it as a number.
Your intuitive distrust of the number should also extend to recurring decimals.
If this is perfectly valid algebra:
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Then nothing stops me having control over the least significant places of these numbers.
I already give you the sum notation to show you can construct these numbers.
These posts are getting a lot closer to what I believe is the answer.
This is the closest to a correct analysis so far.
I'll give my analysis below shortly.
Like the idea that parallel lines cross at infinity, by adding 1 your one shoots off to the start of the set of 0's. It lives at infinity, but it doesn't disappear. If it could disappear at some point then it wouldn't be able to change all the 9's into 0's.
Why can't we say then that 0.999... + x = 1 has the solution x = 0.000...1?
Using the logic of my previous answer, I would say that 0.000...1 = 0 because, in having an infinite amount of zeros before the 1, it is infinitely small and would only contain a 1 if it had a finite number of zeros.

