Then .99 repeating is equal to .99 repeating. It's infinite 9's, you see. This is common sense.
Does 0.999... equal 1?
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Then .99 repeating is equal to .99 repeating. It's infinite 9's, you see. This is common sense.
verryberry10
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fat guy, (lol innaproppriate) the 1 doesnt dissolve into nothingness. Yes, our language has flaws such as this, but it just does not dissapear. okay? Now, start using your head when you post.
Guess what idiot, you proved nothing, you can't do simply fucking mulitplication, WHEN YOU FUCKING MULTIPLY A NUMBER BY 10 IT DOESN'T PICK UP AN EXTRA 1 AT THE END, THEREFORE IT IS 1.111111111.......0. YOU ARE BY FAR THE STUPIDEST MORON I HAVE YET TO SEE IN MY YEARS, YOU DON'T KNOW HOW TO MULTIPLY BY 10. YOU OBVIOUSLY ALSO DON'T KNOW HOW TO DIVIDE, BECAUSE 9/9 = 1, THIS MEANS WE ALL SHOULD LAUGH AT YOUR STUPIDITY.
WhereIsTheGod IS A FUCKING IDIOT
And to you other dumb fucks guess what.
1 - 0.999..... = 0.0000.........1
x=0.999...
10x=9.999....0 DON'T YOU FUCKING GET IT, WHEN YOU MULTIPLY BY 10 YOU DON'T JUST ADD ANOTHER 9.
Its only equal through rounding. If you split the earth into 100,000,000,000,000,000,000 pieces and gave 99,999,999,999,999,999,999 pieces away, you still would have one piece.
EDIT: FIRST INFRACTION
http://en.allexperts.com/q/Advanced-Math-1363/999-1.htm
I think that is the argument most people are using, but it simply doesn't work..
I think that is the argument most people are using, but it simply doesn't work..
The 1 DOES dissolve into nothingness. You cannot have anything come after a patern is repeated infinitely. Infinitely is without end. There is no end to the 0s. Since there is no end you cannot have anything after it. Now, start using your head when you post.
Where are you getting that 0 from?Guess what idiot, you proved nothing, you can't do simply fucking mulitplication, WHEN YOU FUCKING MULTIPLY A NUMBER BY 10 IT DOESN'T PICK UP AN EXTRA 1 AT THE END, THEREFORE IT IS 1.111111111.......0. YOU ARE BY FAR THE STUPIDEST MORON I HAVE YET TO SEE IN MY YEARS, YOU DON'T KNOW HOW TO MULTIPLY BY 10. YOU OBVIOUSLY ALSO DON'T KNOW HOW TO DIVIDE, BECAUSE 9/9 = 1, THIS MEANS YOU ARE THE BIGGEST IDIOT EVER, AND WE ALL SHOULD LAUGH AT YOUR STUPIDITY.
Annex IS A FUCKING IDIOT
And to you other dumb fucks guess what.
1 - 0.999..... = 0.0000.........1
x=0.999...
10x=9.999....0 DON'T YOU FUCKING GET IT, WHEN YOU MULTIPLY BY 10 YOU DON'T JUST ADD ANOTHER 9.
Its only equal through rounding. If you split the earth into 100,000,000,000,000,000,000 pieces and gave 99,999,999,999,999,999,999 pieces away, you still would have one piece.
EDIT: FIRST INFRACTION
.111... is repeated infinitely. The 1s never stop so when you multiply by 10 it moves the 1s over to become 1.111... The ones dont suddenly stop being infinite. And again you cant have anything after the 1s since there is no end to them.
WhereIsTheGod
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Infraction? Fun stuff.
Back to the topic.
Like the fatass1 says - there is no point where you can stick in a zero. It makes no sense to stick in a zero anyway. You use as a placeholder when there is no digit in that slot.
Example:
12 * 10 = 120
Shift the decimal point over, but no digit in the ones slot, so stick a zero there.
You don't need to do this when multiplying decimals
1.2*10 = 12
You can make a case that it has an infinite number of zeroes after the decimal point, but that applies to anything - EXCEPT REPEATING DECIMALS.
Back to the topic.
Like the fatass1 says - there is no point where you can stick in a zero. It makes no sense to stick in a zero anyway. You use as a placeholder when there is no digit in that slot.
Example:
12 * 10 = 120
Shift the decimal point over, but no digit in the ones slot, so stick a zero there.
You don't need to do this when multiplying decimals
1.2*10 = 12
You can make a case that it has an infinite number of zeroes after the decimal point, but that applies to anything - EXCEPT REPEATING DECIMALS.
WhereIsTheGod
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K, sorry for double post, but bump.
Read something in Scientific American that I think will /thread.
If you can produce a number in between .9... and 1, then they are not equal. Otherwise, they are.
Read something in Scientific American that I think will /thread.
If you can produce a number in between .9... and 1, then they are not equal. Otherwise, they are.
0.999 doesn't equal 1. Is that too hard for some of you to figure out? Jesus, some of you need to go back to kindergarten.
We arent talking about .999 here we are talking about .999...(repeated to infinity) the string of 9s goes forever.
Yeah why is people still arguing about this? 0.99999999999999999999999 still doesnt equal 1, no matter how many 9's you add.
No shit Sherlock Holmes? This whole thread is based on it. Next time I'll add the "..." because I know everyone is going to have a hard time contemplating "0.999...", this whole thread is about it.
Its "aren't" not "arent", I can't figure out your post now because of your small grammar error. I'm sorry, no one can understand.
Some of these "bullet proof" arguments are so stupid that I can't believe some idiots actually believe them. "If we round 0.999... to 1, then 0.999... = 1" congratulations, moron.
Well the argument you used was something along the lines of "kindergarteners know .999 doesnt equal 1" so I assumed you dont know what your talking about, and didnt understand that the 9s repeated. Whoever made the "bullet proof" about rounding didnt know what they were talking about. You dont have to round. There are several proofs that have been made here:
and
and
Therefore:
You can attempt to disprove them so long as your argument doesn consist of "random person x provided a flawed argument so now im ignoring the valid ones". Also using "kindergarteners know better" doesnt help your argument especially since I could turn around and say "mathematicians with doctorates know better".
Any dip shit can upload images on image shack and call it proof. Which they all are uploaded on image shack. Every single argument for 0.999... is flawed.
The question is correct, but your answer is wrong (Epic failure). Do you even know why the 0.333... repeats?
I laughed at this one.
Explain this formula too me.
Wrong.
This is pathetic, I should get on ms paint and make "proof".
The question is correct, but your answer is wrong (Epic failure). Do you even know why the 0.333... repeats?
I laughed at this one.
Explain this formula too me.
Wrong.
This is pathetic, I should get on ms paint and make "proof".
Well the argument you used was something along the lines of "kindergarteners know .999 doesnt equal 1" so I assumed you dont know what your talking about, and didnt understand that the 9s repeated. Whoever made the "bullet proof" about rounding didnt know what they were talking about. You dont have to round. There are several proofs that have been made here:
and
and
Therefore:
You can attempt to disprove them so long as your argument doesn consist of "random person x provided a flawed argument so now im ignoring the valid ones". Also using "kindergarteners know better" doesnt help your argument especially since I could turn around and say "mathematicians with doctorates know better".
Your name suits you well. You obviously do need to return to kindergarten, because you have no clue how to derive a decimal from a fraction, to do so you divide the numerator by the denominator. Obviously you made yourself look retarded by posting 3 divided by 3 is 0.9999999999999999999 honestly, I never knew someone could be this stupid, your education system failed you fatass, because you can't grasp the fact that 3 divided by 3 is 1. Until you master that, maybe you should shut up? Now for your stupid 10x= method, when you multiply an infinite number by 10, (which isn't possible) you remove the last place, because when you move the decimal over 1 place, you don't spawn another 9 when you do that, thats not mathematics. You are left over with a single infinitely small .00000...1. So you can't subtract that from x, because they aren't the same, and your equation therefore fails.
What is your definition of "infinity" fatass?
Tim the Tool Man Allen agrees with me:
Thats what your proof is fatass.
Tim the Tool Man Allen agrees with me:
Thats what your proof is fatass.
When you do the long division you continuosly get 3.Any dip shit can upload images on image shack and call it proof. Which they all are uploaded on image shack. Every single argument for 0.999... is flawed.
The question is correct, but your answer is wrong (Epic failure). Do you even know why the 0.333... repeats?
Why?I laughed at this one.
Explain this formula too me.
The number .999...
Is n number 9s as n approaches infinity.
The greek simbol sigma can be used to represent sums the bottom k=1 means that we are using k as the incrimenting variable. The top number is then number to stop summing at. So if we wanted to sum from 1 to 3:
In this case we want the sum to approach infinity so we make n approach infinity.
It can also be writtin without the sigma simbol using 1-1/10^n
The limit of 1-1/10^n as n approaches infinity is 1 since 1/10^n becomes infinitely small it becomes 0.
therefore
You could also use the geometric series theorem. r=1/10 and a=.9
so the sum of the series is .9/(1-0.1)=.9/.9=1
Why?Wrong.
Again an attack directed at me without disproving my arguments. It only weakens yours. I would very much like to see your attempt at disproving me, using valid logic and not attacks.
If in fact 1=.999... then 3/3=.999...
You can indeed multiply an infinitely repeated decimal. Nothing is left empty since everything is filled with 9s. Again you cannot have 1 one past an infinitely repeated decimal, every place is already filled with 0s.
When you do the long division you continuosly get 3.Why?
The number .999...
Is n number 9s as n approaches infinity.
The greek simbol sigma can be used to represent sums the bottom k=1 means that we are using k as the incrimenting variable. The top number is then number to stop summing at. So if we wanted to sum from 1 to 3:
In this case we want the sum to approach infinity so we make n approach infinity.
It can also be writtin without the sigma simbol using 1-1/10^n
The limit of 1-1/10^n as n approaches infinity is 1 since 1/10^n becomes infinitely small it becomes 0.
therefore
You could also use the geometric series theorem. r=1/10 and a=.9
so the sum of the series is .9/(1-0.1)=.9/.9=1
Why?Again an attack directed at me without disproving my arguments. It only weakens yours. I would very much like to see your attempt at disproving me, using valid logic and not attacks.
If in fact 1=.999... then 3/3=.999...
You can indeed multiply an infinitely repeated decimal. Nothing is left empty since everything is filled with 9s. Again you cannot have 1 one past an infinitely repeated decimal, every place is already filled with 0s.
I explained in my top post, but I'll do it again:
What is you definition of "infinity"?
You get a continuous 3, because the answer is limitless (Infinity). What is 3 divided by 3? Is it .999...? Moron.
As for 10x = 9.999
Annex explained it nicely.
Now this formula you have supplied, it wont work because infinity is limitless. It means you won't ever be able to reduce to 0, meaning epic failure. If infinity is limited, then by all means, prove it. Because the proof you have supplied is invalid, this is an example:
Just because Tim Allen says so, does it mean its true? HELL YA IT DOES.
Without end.
Because 1=.999... then 3/3=1=.999...
I already responded to that.
Um... what? Read up on limits:
http://en.wikipedia.org/wiki/Limit_(mathematics)
Ummm... no.Because the proof you have supplied is invalid, this is an example:
Just because Tim Allen says so, does it mean its true? HELL YA IT DOES.
Nope.
1 does not have 2 values. Its either 1 or its not.
1 does not have 2 values. Its either 1 or its not.
1 does not have 2 values. It simply has multiple ways to write it.
1=1/1=2/2=3/3=4/4=5/5=1.0=1.00=1.000...=.999...=1^2=1^3=1^(1/2)=1^(1/3)=2*3*(1/(36^(1/2)))
Hmm... You say they are differnt values? None of them are equal?
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