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Can't be bothered figuring it out lol, maybe if it had a joke for an answer then i would but it doesn't.
oh man, its too late in the day to be working these things out.. try... to..morrow..
Interesting.
Second, its C.
Second, its C.
my theory: 50/50
because: split the chances 1/3 up to 2/6 (its the same)
If B is released, he HAD a chance of 2/6, which is now split equally to prisoner A and B, resulting each gaining 1/2 of the 2/6 which is 1/6
They already had 2/6, so if they gain 1/6, they will eventually have 3/6, and 3/6 is equal to 1/2 resulting, A and B have the same chance.
because: split the chances 1/3 up to 2/6 (its the same)
If B is released, he HAD a chance of 2/6, which is now split equally to prisoner A and B, resulting each gaining 1/2 of the 2/6 which is 1/6
They already had 2/6, so if they gain 1/6, they will eventually have 3/6, and 3/6 is equal to 1/2 resulting, A and B have the same chance.
i still think its 50/50 because only 2 get released (1 beeing B)
now your left with A and C now each of them have equal opportunity to get out because he cannot reveal the fate of A because he asked, there for they both have equal chance.
or since he is able to speak to the warden then he is probably all ready beeing released he just wants to know with who.
now your left with A and C now each of them have equal opportunity to get out because he cannot reveal the fate of A because he asked, there for they both have equal chance.
or since he is able to speak to the warden then he is probably all ready beeing released he just wants to know with who.
C
Cruel__Machine
Guest
I'll try to make it more like the Monty Hall problem so it can be better understood...
Ok... say you were to choose which prisoner was to ask the warden. You have a 2/3 chance of choosing a prisoner that is to be released, correct? And every time you choose a prisoner that is to be released, the warden will reveal the other prisoner that is to be released to them, and the person left over will therefore be the one sentenced to death.
So if the situation is like that 2/3 of the time when you choose the prisoner to ask, then the probability of the third person to be sentenced to death would be the same, 2/3.
But like Steph mentioned from the wiki... if A had asked "Will B be released?", the warden would've said yes, and A and C's probability would be the same, 1/2.
Ok... say you were to choose which prisoner was to ask the warden. You have a 2/3 chance of choosing a prisoner that is to be released, correct? And every time you choose a prisoner that is to be released, the warden will reveal the other prisoner that is to be released to them, and the person left over will therefore be the one sentenced to death.
So if the situation is like that 2/3 of the time when you choose the prisoner to ask, then the probability of the third person to be sentenced to death would be the same, 2/3.
But like Steph mentioned from the wiki... if A had asked "Will B be released?", the warden would've said yes, and A and C's probability would be the same, 1/2.
Who cares what the answer is just say its 50% 
Um...
All 3 don't know whose gonna die they all have a 66.6 chance of dieing.
Then A knows B is gonna live. Doesn't that make it 100% that A and C are gonan die?
All 3 don't know whose gonna die they all have a 66.6 chance of dieing.
Then A knows B is gonna live. Doesn't that make it 100% that A and C are gonan die?
C
Cruel__Machine
Guest
ROFL... reread it.
Only 1 of them will die.
0_0 oh rofl! I was like.... wdf am I missing here?
isosceles
Forum Addict
/win
I love this problem. Nobody ever believes the correct answer
I love this problem. Nobody ever believes the correct answer
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