BotWatch Detection Systems Added to Dungeoneering!

I feel like goldfarmers will be some of their last targets. Here's why:

1 person will run an army of accounts. If one of them gets banned, they don't give a fuck because they'll just make a new one and start over. They still profit nicely despite the bans, so Jagex spending all their time banning these accounts in the current time will not really do much to efficiently get rid of them or lower their numbers. In addition, as soon as they attack one goldfarming location, these farmers will simply adapt and move their fleet to a different gp source. It'd be a wild goose chase and it would not only waste Jagex's time and money, but it wouldn't be an efficient way to go about targeting them.

Jagex can scare a shitton of players from botting by targeting places that are common for normal players. When Jagex shows they are banning high profile accounts in areas that are popular to bot at with mains or other valuable accounts, it has a psychological effect on the botting community. Look at the dung bans for example; how many people in this thread have said they will not be botting dungeoneering or using iDung because of this implementation? Eventually once they cover all normal training spots, if they are banning like they have been at LRC & Daemonheim, how many normal players do you think are going to bot?

Once all of these regular spots have been covered, there will still be a very small percentage of people botting successfully on their mains and such, but goldfarming locations will be lit up like a fucking beacon on their BotWatch Radar Map. If they do it this way, once all of the goldfarming locations are covered, these farmers won't have any other locations to alternate to because they would have already covered it prior to the attack against goldfarmers.

You gotta look at it from a business and economic standpoint; what is the most efficient way for these BotWatch developers to launch their full sweep and blanket the entire RS map without wasting time or money? The answer is what I said above. Simple as that.