Free homework help here

[MatthewGor123]

unb4nn3d, point (3) doesn't work, does it?

I would also find the gradient by differentiating the equation (once simplified sufficiently) with respect to x in order to find the gradient function. Then substitute 2 in as the value for x.

EDIT: Damn Matthew, beating me to it.

Sorry mate .

Fat, you want to take this one, as neither of us really have too much of a background with calculus? I could add you to the official helpers list ^_^

 

[FlubbyWubs]

Ok, well Im doing geometry - Proofs? Double congruency, stuff like that. Im having MAJOR issues and was wondering if anyone knows a good website or a good book that could help me out?

 

[MatthewGor123]

Ok, well Im doing geometry - Proofs? Double congruency, stuff like that. Im having MAJOR issues and was wondering if anyone knows a good website or a good book that could help me out?

Ooh, I loved proofs last year for Geometry. Most people in my class hated it, lol. The textbook we used was: "Geometry for Enjoyment and Challenge", by Richard Rhoad, George Milauskas and Robert Whipple and published by McDougal Littell.

If you have any specific questions, I'd be more than willing to help

 

[The Fat Controller]

I don't actually seem to be able to do the question I can't find any simple ways of doing it.

yx - y = [2x(x^2+3x-4)+4x-4] = 2x^3 + 6x^2 - 4x - 4

y + dy/dx(x) - dy/dx = 6x^2 + 12x - 4

Then what?

 

[MatthewGor123]

I don't actually seem to be able to do the question I can't find any simple ways of doing it.

yx - y = [2x(x^2+3x-4)+4x-4] = 2x^3 + 6x^2 - 4x - 4

y + dy/dx(x) - dy/dx = 6x^2 + 12x - 4

Then what?

Well, then I guess we were stumped *sniffles*

Homework sheet 1 :

Q1: 1 + 1

NEED HELP PL0X!

[SARCASM]As this isn't a mathematical equation, and you don't specify anything that seems necessary to be done, I think you're stuck with 1 + 1[/SARCASM]

 

[FlubbyWubs]

Ooh, I loved proofs last year for Geometry. Most people in my class hated it, lol. The textbook we used was: "Geometry for Enjoyment and Challenge", by Richard Rhoad, George Milauskas and Robert Whipple and published by McDougal Littell.

If you have any specific questions, I'd be more than willing to help

Oh, wow lol. I cant stand it, so damn annoying. Takes like 20 min to do one of them. Okay well either way thanks for the book =] if I need anything i'll let you know

 

[MatthewGor123]

Oh, wow lol. I cant stand it, so damn annoying. Takes like 20 min to do one of them. Okay well either way thanks for the book =] if I need anything i'll let you know

I'll be waiting I haven't done a proof in ages, gimme one to do. Gotta stay fresh, ya know ^_^

I NEED AN ANSWER!

i thought you were smart

You didn't ask a question. 1 + 1 doesn't mean anything.

 

[m0ck3r]

1 + 3 - 2 + 7 x 36 - 10 + 102 x 6

solve pl0x !

 

[FlubbyWubs]

1 + 3 - 2 + 7 x 36 - 10 + 102 x 6

solve pl0x !

2496. What level math is this lol? I figured this out in my head.

 

[ivirz]

What is the gradient of the function y = [2x(x^2+3x-4)+4x-4]/[x-1] when x = 2?

____________________________

Lets see...
Assuming gradient is the slope of the line, you'll need to take the derivative of the above function. In its current state, the derivative would take a lot of work to complete, so first, youll need to simplify the function.


As others have already stated, the function can be simplified to:

y = [2x^3+6x^2-4x-4]/(x-1)



You can take the derivative from here, but that still requires a lot of work. The function can be simplifed further by factoring (x-1) out of the numerator. Typing the algebraic long division would be quite tricky, but the actual simplyfied version will look something like:

y=2x^2+8x+4

(If I get a chance, Ill try to post a picture of this step, as I really havent explained it much >.<)



From here, taking the derivative is a lot easier:

dy/dx = d/dx (2x^2+8x+4)

dy/dx = 4x + 8



Then it is simply a matter of inputing 2 as your x variable:

dy/dx (2) = 4(2) +8

dy/dx (2) = 16

Thats the solution I've come to. Not sure if its right (agian, not even sure if gradient refers to slope). But anyways, hope it helps!

 

[MatthewGor123]

NO YOU DIDNT LIAR!

this is what he did

Start > All Programs > Accessories > Calculator


STOP LIEING!

slanter & lies

Stop fucking spamming :S

What is the gradient of the function y = [2x(x^2+3x-4)+4x-4]/[x-1] when x = 2?

____________________________

Lets see...
Assuming gradient is the slope of the line, you'll need to take the derivative of the above function. In its current state, the derivative would take a lot of work to complete, so first, youll need to simplify the function.


As others have already stated, the function can be simplified to:

y = [2x^3+6x^2-4x-4]/(x-1)



You can take the derivative from here, but that still requires a lot of work. The function can be simplifed further by factoring (x-1) out of the numerator. Typing the algebraic long division would be quite tricky, but the actual simplyfied version will look something like:

y=2x^2+8x+4

(If I get a chance, Ill try to post a picture of this step, as I really havent explained it much >.<)



From here, taking the derivative is a lot easier:

dy/dx = d/dx (2x^2+8x+4)

dy/dx = 4x + 8



Then it is simply a matter of inputing 2 as your x variable:

dy/dx (2) = 4(2) +8

dy/dx (2) = 16

Thats the solution I've come to. Not sure if its right (agian, not even sure if gradient refers to slope). But anyways, hope it helps!

Though I don't really understand the derivative part, or the long division part [are you sure it's accurate?], if this is correct, then thank you so much for helping out on this thread If not, well, I applaud your effort

 

[ivirz]

Though I don't really understand the derivative part, or the long division part [are you sure it's accurate?], if this is correct, then thank you so much for helping out on this thread If not, well, I applaud your effort

The derivative part is correct. I've just double checked on a calculator, and indeed, the slope of line y at 2 is 16, so the math is correct. The long division was done correctly as well, seeing as the answer was right... Just really hard to show via typing.

Hey, glad to help. Im sorry that i couldnt explain more, Ill have to start using diagrams. Im sure you can understand that typing math isnt easy. Anyways, if any more calculus problems arise, Ill be lurking.

 

[The Fat Controller]

1 + 3 - 2 + 7 x 36 - 10 + 102 x 6

solve pl0x !

We need someone with a banhammer to get rid of this 10 year old. 4chan is where he/she/it belongs.

y=2x^2+8x+4

(If I get a chance, Ill try to post a picture of this step, as I really havent explained it much >.<)

Oh, polynomial division. I wasn't thinking along those lines, but that would work if done correctly. Am I right in thinking there is no remainder either, since substituting +1 into the numerator gives an answer of 0?

 

[LJ6580]

What is the gradient of the function y = [2x(x^2+3x-4)+4x-4]/[x-1] when x = 2?

____________________________

Lets see...
Assuming gradient is the slope of the line, you'll need to take the derivative of the above function. In its current state, the derivative would take a lot of work to complete, so first, youll need to simplify the function.


As others have already stated, the function can be simplified to:

y = [2x^3+6x^2-4x-4]/(x-1)



You can take the derivative from here, but that still requires a lot of work. The function can be simplifed further by factoring (x-1) out of the numerator. Typing the algebraic long division would be quite tricky, but the actual simplyfied version will look something like:

y=2x^2+8x+4

(If I get a chance, Ill try to post a picture of this step, as I really havent explained it much >.<)



From here, taking the derivative is a lot easier:

dy/dx = d/dx (2x^2+8x+4)

dy/dx = 4x + 8



Then it is simply a matter of inputing 2 as your x variable:

dy/dx (2) = 4(2) +8

dy/dx (2) = 16

Thats the solution I've come to. Not sure if its right (agian, not even sure if gradient refers to slope). But anyways, hope it helps!

That's great, I'm just happy others can do this kind of math on the forum. I thank everyone for their time and effort, and I thank you Ivirz for solving the problem that they couldn't.

Edit: And oh yes, it is correct 100%. You guys can learn from him.

 

[MatthewGor123]

That's great, I'm just happy others can do this kind of math on the forum. I thank everyone for their time and effort, and I thank you Ivirz for solving the problem that they couldn't.

Edit: And oh yes, it is correct 100%. You guys can learn from him.

We have said, none of us have ever taken a calculus class. But yeah; he helped ya, so that's all that counts Glad everything worked out for ya in the end .

 

[Badonkadonk]

please help me with this

 

[luke99]

1=1

 

[Shin]

please help me with this

Let the height of the rectangle be h, and the diameter of the circle be x. The base of the rectangle is obviously equal to the diameter of the circle.

The semicircle has a radius (r) of x/2

Circumference of the semicircle = (pi/2)x

Perimeter is: P = (pi/2)x + x + 2h = 30

2h = 30 - ((pi + 2)/2)x
h = 15 - ((pi + 2)/4)x

The area of a semicircle is pi * r^2 / 2, or pi * ((x/2)^2) / 2, or (pi/8)x^2

An area of a rectangle, base * height, is x * h.

The total area is, therefore, (pi/8)x^2 + xh

Since we already solved for h, we can plug this back in to this, giving:

(pi/8)x^2 + x(15 - ((pi + 2)/4)x)

You can simplify this, but it's really not necessary. All you have to do, since you can pretty easily see that this will be a parabola, is graph that function. Yes, it's a bitch to enter on the calculator, but it's doable (there is only 1 variable, so simplifying it further won't do anything anyways, in terms of graphing).

Basically, when you graph this (Gcalc.net), you see this:

If you have a graphing calculator, now would be a good time to use one. If not, well, I'm not going to explain how to find the limit (x) of a quadratic, but you will find that the point where the parabola shifts (the vertex) is (8.4014861, 63.011155). So, the dimension for x = 8.4014861. To make sure we don't make any rounding errors early on, let's leave it as 8.401.

So, now that we have x, we can plug this back in for h;

h = 15 - ((pi + 2)/4)*8.401
h = 15 - (1.28539816*8.401)
h = 4.201370058

So, rounding to the nearest 10th, the width of the rectangle (or diameter of the circle) is going to be 8.4, and the height of the rectangle is going to be 4.2.

He PM'd me this, because he didn't want to post it himself. I don't know why.

 

[wtp]

Damn you got a sticky. Congratulations you deserve it. Your very dedicated.

 

[draiktame]

2496. What level math is this lol? I figured this out in my head.

obviously not low enough for you..
the correct answer is actually 1108
please exscuse my dear aunt sally..

please that's kindergarten garbage.