Free homework help here

I'm looking forward to trying to help ^_^ Just have some confidence; anyone can learn math if they really just focus on it in school and outside of it.

 

um just answer that one show me steps

 

Okay, so you have f(x) = 2/(3x+5)? or f(x) = (2/3) * (x+5) or, what you actually wrote, f(x) = (2/3x) + 5? Could you be a bit more specific in what you want to know? What am I solving for? Do you want to see a graph? Or do you want me to find its inverse?

All you said is:

Yes, I understand it. But what do you want me to do with this understanding?

 

f(x) = (2/3x) + 5

thats it and a graph

 

nvm here is the problem


f(x)=(3/4x)-3
can u solve that with a grid and table? and give me the x intercept and the y intercept

 

Okay, sure. The x intercept is going to be the point where y = 0, right?

So, 0 = (3/4x) - 3
3 = 3/(4x)
12x = 3
x = 1/4.

So, the x-intercept is (0, 1/4).

The y-intercept is the point where x = 0, so...
y = 3/(4*0) - 3...we run into a problem; you cannot divide by 0. Therefore, this graph does not have a y-intercept. The graph is asymptotic to the y-axis (x=0).

A table of points...you can make that yourself, right? Just pick values for x until you can find the general trend. I'll give you a hint; y can never be equal to 3 (the graph is asymptotic to y=3). Just pick random points. For your reference, here's a graph of the function:

 

need big help, Heres what i need.



And its pythagoras theorem.. if anyone can help, it will be greatly appreciated..

 

What is the gradient of the function y = [2x(x^2+3x-4)+4x-4]/[x-1] when x = 2?

 

Okay, so you know that the distance from AB is going to be sqrt((x2 - x1)^2 + (y2 - y1)^2), where x is the x-coordinate, y is the y-coordinate, and the 1 represents A, and the 2 represents B. This is by Pythagoras' theorem; If you were to draw a right triangle, the hypotenuse [distance from A to B] is equal to the root of (leg1 (x2 - x1) squared plus of leg2 squared (y2 - y1))

For the first one, x2 = 6, and x1 = 1, y2 = 9, y1 = 0.

So, the answer is going to be sqrt((6-1)^2 + (9-0)^2), or sqrt(25 + 81), so sqrt 106 ](the square root of 106)].

The second one, x2 = 9, x1 = 1, y2 = 1, y1 = 9.

So, you have sqrt ((9-1)^2 + (9-1)^2), or sqrt (64 + 64) or sqrt (128). So, the answer is going to be the square root of 128.

Please don't hesitate to ask for further clarification.

Sorry, I'm not so sure how to do this I'm not quite sure on the definition of gradient.

 

The Pythagorean Theorem is this

a² + b² = c²

So, with the following information of points in the graphs you have:

Graph 1

(1,0) and (6,9)

These points create the following Triangle



So, use the Pythagorean Theorem.

5² + 9² = c²
25 + 81 = c²
106 = c²

Then use the square root of both sides:

√106 = √c²

You will then cancel out the ² in c², leaving you with:

√106 = c


The factors of 106 are:

1 2 53 106

Since 106 has no Perfect Roots Factorable, √106 = c is your answer.


Graph 2

(1,9) and (9,1)

These points create the following Triangle



So, use the Pythagorean Theorem.

8² + 8² = c²
64 + 64 = c²
128 = c²

Then use the square root of both sides:

√128 = √c²

You will then cancel out the ² in c², leaving you with:

√128 = c

Simplify:

8√2 = c

The factors of 128 are:

1 2 4 8 16 32 64 128

Since 64 is a perfect square of 8, you get the answer of 8√2 for c

From the beginning of this problem, you could tell that 8√2 was the answer.
This is because both lines A and B were the same.
-This means the triangle will be a 90, 45, 45.

When this occurs, you get the following:



In front of the √2 is obviously a 1, which is useless to be put.

So, in doing so, you know that if 8 are both sides, you will get 8√2 based on the triangle.

There is also the triangle of a 30-60-90, which gives the following:



If you cannot remember the exact sides for the triangle, use the Law of Sines

The Law of Sines is as follows:



So, you can do the following:



Since this triangle is proportional, the answer of both sides should give you "2"

-------------------------------------------------------------------------------

PLEASE NOTE:

This also could have been solved using the Distance Formula. =D
-Was what I was originally going to do, but you insisted to use the Pythagorean Theorem.

All pictures provided were made and created by Unb4nn3d.

Have fun with Math! =D!

 

Thanks guys! i read what matthew said and wasnt so sure.. im not so good with mathes.. but yours unb4nn3d was really helpful!, i got 100% on my online test! which means im in a new group with my girlfriend!!!

Thanks alot

 

No problem Swivvy. It took me about 30 minutes to make that post, lol.

All the pictures I had to make an put in extreme detail took a while.

I hope to be of assistance in the future. =D

 

Yup, sorry - I just whipped mine up in like 3 minutes; but that's the benefit of having a partner in crime to clean up my shit

Glad you got a 100%

 

Yes, and you should take more time to make such posts! Lol.

I am now officially an addition to MatthewGor123's thread, and will be helping out for all that need Math Support / Tutoring. If you need to see a quick Bio about myself, you can find that on Page 1.

I hope to help people out with any questions that come, and they will be answered within reasonable time.

 

Well, I was planning on modifying it after getting back from tennis; I had tennis at 4:00 [so I should have left the house around 3:30] and I knew I wouldn't get home till 7:00, so I just wanted to get the post done as fast as possible and then modify it if there are any questions.

But you gave a sweet response, so it wasn't necessary ^_^

 

If anyone can get me the answer, that would be awesome. I'm just wondering who is at what level here, so just give it your best shot. Show your work if you want to actually learn from this problem.

 

I would have simplified the numerator, try to factorize it with an (x-1) up top, cancel the fraction, and then try to differentiate it. I've only tried for a minute, but I can't find a way to factorize the top.

 

I will say right now that I have no clue what a gradient is, but I looked it up for an hour.

I have tried and tried to find an explanation, but I cannot find the answer I'm looking for.

So, I tried to do this problem out like so.

I will say right now that I have no clue what a gradient is, but I looked it up for an hour.

I have tried and tried to find an explanation, but I cannot find the answer I'm looking for.

So, I tried to do this problem out like so.



Well, I just had to re-edit the entire picture.. and found out something.

I solved this equation in Grads, not Gradients.

Sorry.. I'll try to find out how to do Gradients later on.. very confusing.

http://en.wikipedia.org/wiki/Gradient

I'm sure the answer is not correct, but the important thing to me is that I tried.

Maybe ask your teacher or professeur for help, as that's why they are always there.

Hopefully I helped. =D Take care.

 

You make a critical error early on. You can't factor out (x-1), as it is separated from the numerator through addition. If you test it numerically, the simplified rule yields 60, but the unsimplified rule gives 28, when x=2. Sorry - you're definitely on the right track [I think, if that's actually what gradients means...which I'm not sure it does]

EDIT: Gradients are not the same as Grads...you're using Grads, while he's looking for Gradients :'(
http://en.wikipedia.org/wiki/Gradient vs http://en.wikipedia.org/wiki/Grad_(angle)

 

unb4nn3d, point (3) doesn't work, does it?



I would also find the gradient by differentiating the equation (once simplified sufficiently) with respect to x in order to find the gradient function. Then substitute 2 in as the value for x.

EDIT: Damn Matthew, beating me to it.