X_Deity_X is a scammer

these are all the messages he sent me before i gave the code:
i buy 1600?

first of all...i aint going first 2 yu....second of all if its mm u want sort its out call a omm and sort it out i dont mind tbh but i dont go first especially when im trusted and i do actually have vouches

yup yu only have 1 vouch...meaning i am more trusted and i am trusted as a whole anyway but if its a mm yu want i only do deals with omm's and i aint paying for it. koz mm's they really are scammers...thats the only reson they go free

who cares lol i aint paying for a omm...i dont really plan on paying extra for a omm ...i am paying extra already as it is for the code :S so i dont relaly mind if yu dont wish yu trade with me but i just want youu to know.

nty..i am not sendin irl money first....especially when im more trusted than yu ... it dont make sense tbh? whats the point in having trust and vouches when it doesnt make a difference with ur trades?

im sorry im not sure yu got my pm the other time

i am not going first and i do not deifnantly sned irl money first...dude i am trusted and i do wanna buy ur code but not if it involves me going first to yu when ur new to these forums and got a lower trust rep than me

yup just send me ur paypal along wiht the code

ok so lemme know are we trading?


Quote:
Originally Posted by nykicks
Quote:
Originally Posted by X_Deity_X
ok so lemme know are we trading?
yes

payment to: TOOK IT OFF TO PROTECT MYSELF
code: DM6WC-26KJC-PPXK8-GGW29-JCCMJ

yesh its invalid ... did yu miss type or is this a test of somesort?

so are we going to trade seriously?

/....welll?





now may i point out that i never go the payment and right after he said that the code was "invalid" i tried to redeem it and it said that the code was valid but it was already redeemed.


i know he is banned but i never want him to go on from another user name again. although he is banned, it doesn't put 20 dollars back in my pocket.

 

He seems to have been hacked, but in order for him he must pay you back with sufficient proof.