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What was the 500m/hr method anyways?

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Matthew905

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What was the 500m/hr method anyways?

j/w :D!
 
decanting potions
 
You can find it in rsbots.net and powerbot.org i think.

well it was about the receiving account buying (4) potions.

Eg. (4) pots cost 60gp

then the receiving account would teleport to Nardah , and decant the potions into (2). The loophole here is that the (2) potion was 30gp, which meant that they did not count the value of the vial in.

The, then receiving acc would trade the giving acc and the money xferred would be the cost of vials.

so if you bought 100K potions, you would transfer 1.5mil in ONE trade!
 
uselesspoop said:
You can find it in rsbots.net and powerbot.org i think.

well it was about the receiving account buying (4) potions.

Eg. (4) pots cost 60gp

then the receiving account would teleport to Nardah , and decant the potions into (2). The loophole here is that the (2) potion was 30gp, which meant that they did not count the value of the vial in.

The, then receiving acc would trade the giving acc and the money xferred would be the cost of vials.

so if you bought 100K potions, you would transfer 1.5mil in ONE trade!
Click to expand...

but you cant decant 100k pots in 1 hr and even if you could you wouldnt be able to do that enough to make 500 mill a hr
 
you can, remember the new update :P

the man at ge can help u decant NOTED potions, as many as you like, for free!

also , nardah will decant noted potions, as many as you like , for free!
 
You basically took pots that were (4) tele to nardah, turn them into 2x the amount of (4) potions (2). So if you had 100k (4) you would get 200k (2), you would then tele to varrock, trade them, and the account receiving gp woudl decant and get 100k Pots and 100k Vials, so the amount transfered would be the amount of vials. so if you had 100k vials it was 1.6m a minuet. I was able to have 1.9m pots, so I was doing 28mish a run.
 
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So any kind of pots would've worked really well with the method then o_O?
 
..I'm guessing it doesn't work anymore?
 
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