J JJCXD Newcomer Joined May 23, 2011 Sythe Gold 5 Messages 13 Oct 4, 2016 #1 4x(3x-2)-5x(2x-4)=2x^2+7 I need to find out the "x" value
Program Formerly known as Andy Samberg Joined Sep 17, 2015 Sythe Gold 902 Messages 5,003 Oct 4, 2016 #2 Correct me if I'm retarded, but wouldn't it be something like this? 4x(3x-2) - 5x(2x-4) = 2x^2 + 7 12x^2 - 8x - 10x^2 + 20x = 2x^2 + 7 2x^2 + 12x = 2x^2 + 7 12x = 7 x = 7/12 Last edited: Oct 4, 2016
Correct me if I'm retarded, but wouldn't it be something like this? 4x(3x-2) - 5x(2x-4) = 2x^2 + 7 12x^2 - 8x - 10x^2 + 20x = 2x^2 + 7 2x^2 + 12x = 2x^2 + 7 12x = 7 x = 7/12