(3x^2) + 5x + 2 = 0
(3x^2) + 5x = -2
x (3x + 5) = -2
Set both equal to zero:
x = 0
And:
3x + 5 = 0
3x = -5
x = -5/3
The two holes in the graph are x = 0, and x = -5/3.
And don't double post. >.<
You forgot the -2 you put on the right side of the equation. I would try factoring a little differently.
3x^2 + 5x + 2 = 0
Factor the whole thing. This takes a bit of practice and intuition. You have to think backwards sort of. You will start to see some patterns:
(3x + 2)(x + 1) = 0
Now look, If (3x +2) OR (x + 1) is equal to 0, the WHOLE thing will be equal to 0.
(x + 1) = 0 when x = -1.
(3x + 2) = 0 when x = -2/3.
Now plug the numbers back in and see if they work to check it.
Therefore, the graph of this function would intersect the x axis at (-1, 0) and (-2/3, 0).
Please, if you don't understand any of the steps or if you want me to explain the factoring I did a little more, tell me. There is no use for me to explain this if I'm not helping you understand it. If you do not understand this math, it will come back and bite you later when you go into more complex problems.
I sometimes skip steps simply because I have done quite a few problems. When you are learning something new, this is not a good idea. If you want me to go into more depth, tell me. I'm trying to help people get a better
understanding of math

.