MM_Alex
Forum Addict
Ah, the most simple of all equations, the linear.
The Balancing method
this is basically the principle of what you do to one side you MUST do to the other
For a simple example:
x + 2 = 4
now we want to find the unknown, x. So we shall take away 2 from both sides
-2 x + 2 = 4 -2
leaving us with:
x=2
slightly more complicated
2x = 0
Now we shall divide both sides by 2 ( as once again we wish to find the variable x )
This leaves us with
x = 0
as complicated as it gets
Of course, i'm not going to make a-hundreds-of-pages long equation but i will introduce some new factors, namely fractions.
( to show a fraction i will put the nominator [top part] in these brackets "[ ]" and to show the line between the nominator and denominator [bottom part] i will seperate with "/"
eg
[x]/2 = 2
Now we can cross multiply for simple equations like this. However this is a very method and can only work for small equations. So we wont
we will use a multiplier
this is basically the lowest common factor of the fractions
ie,
[x]/2=2
can also be written as
[x]/2=[2]/1
the lowest common factor is 2 so we multiply both sides by 2 leaving us with:
x=4
a harder example
[x+2]/4 = [2x]/2
in this case first of all we multiply both sides by 4 (lowest common multiple)
this gives us:
x+2= 2[2x]
(we get the 2[2x] as we multiples [2x]/2 by 4 which means the [2x] is multiplied by 2)
we then multiply out the brackets giving us:
x+2 =4x
we then - x from both sides to give us:
2 = 3x
we then divide both sides by 3 giving us:
x = [2]/3 or 0.6666666........
and that is pretty much all...
thanks for reading this was my first guide so please tell me what u thought
The Balancing method
this is basically the principle of what you do to one side you MUST do to the other
For a simple example:
x + 2 = 4
now we want to find the unknown, x. So we shall take away 2 from both sides
-2 x + 2 = 4 -2
leaving us with:
x=2
slightly more complicated
2x = 0
Now we shall divide both sides by 2 ( as once again we wish to find the variable x )
This leaves us with
x = 0
as complicated as it gets
Of course, i'm not going to make a-hundreds-of-pages long equation but i will introduce some new factors, namely fractions.
( to show a fraction i will put the nominator [top part] in these brackets "[ ]" and to show the line between the nominator and denominator [bottom part] i will seperate with "/"
eg
[x]/2 = 2
Now we can cross multiply for simple equations like this. However this is a very method and can only work for small equations. So we wont
we will use a multiplier
this is basically the lowest common factor of the fractions
ie,
[x]/2=2
can also be written as
[x]/2=[2]/1
the lowest common factor is 2 so we multiply both sides by 2 leaving us with:
x=4
a harder example
[x+2]/4 = [2x]/2
in this case first of all we multiply both sides by 4 (lowest common multiple)
this gives us:
x+2= 2[2x]
(we get the 2[2x] as we multiples [2x]/2 by 4 which means the [2x] is multiplied by 2)
we then multiply out the brackets giving us:
x+2 =4x
we then - x from both sides to give us:
2 = 3x
we then divide both sides by 3 giving us:
x = [2]/3 or 0.6666666........
and that is pretty much all...
thanks for reading this was my first guide so please tell me what u thought





