Thanks for the help. I was still trying to find a way to solve it. Found the coordinates (0, 5) and (3, -4).
3x + y = 5
y = 5 - 3x
x^2 + (5 - 3x)^2 = 25
x^2 + 9x^2 - 30x + 25 = 25
10x^2 -30x = 0
x^2 - 3x = 0
x(x - 3) = 0
x = 3 or x = 0
3 x 3 + y = 5 or 3 x 0 + y = 5
9 + y = 5 or y = 5
y = -4 or y = 5
(3, -4) or (0, 5)
Look right?
Can this method used in the second graph? You would get:
xy = 8
x = 8 / y
(8 / y)^2 + y^2 = 20
64 / y^2 + y^2 = 20
64 / y^2 = 20 - y^2
64 = 20y^2 - y^4
y^4 - 20y^2 + 64 = 0
p^2 - 20p + 64 = 0 (x^2 = p, easier to calculate)
(p - 16)(p - 4)
p = 16 or p = 4
x^2 = 16 or x^2 = 4
x = 4 or x = -4 or x = 2 or x = -2
(4, 2) or (-4, -2) or (2, 4) or (-2, -4)