2nd Pythagorus Theorem Sum

[G0ld3n_Sk1llz]

Right Angled Triange

FIND THE VALUE OF X

hmm. i need to get pics but il try explain best as i can
12.4km short side (adjacent)
32.5km (opp)
X - Find the Value

3 terms are
SIN
COS
TAN


other terms are

OPP
HYP
ADJ


PLEASE POST WORKING OUT IF YOU DO THIS I WILL DO ANYTHING YOU ASK

 

[†Tysonâ€Â]

So is x a side or is it an angle? coz if its an angle then you use tan (opposite over adjacent).

 

[G0ld3n_Sk1llz]

x is the side but it is neither opp or adj
32.5km is the opp
an 12.4km is the adj

 

[Cfrey]

Well its 4 in the morning. Way too late to be doing math. Don't wanna risk screwing it up for ya so just remember...

SOHCAHTOA
SIN - Opposite over Hypotenuse
COS - Adjacent over Hypotenuse
Tan - Opposite over Hypotenuse

meh I think those are right. I could help you later if you add my msn and ask for help when I am actually awake. Please try not to make too many topics over your homework, just keep going with the same topic using new problems in new posts. (Don't double post either)

 

[G0ld3n_Sk1llz]

yeah i no sohcahtoa

 

[SnakeyekanS]

Right Angled Triange

FIND THE VALUE OF X

hmm. i need to get pics but il try explain best as i can
12.4km short side (adjacent)
32.5km (opp)
X - Find the Value

you have to find the hypotenuse (x)
formula is

c2 = a2 + b2 c=hyp a=adj b=opp

x2= 12.4(2) + 32.5(2) (2) = squared

x2= 153.76 + 1056.25

x2= 1210.01

x= Square root of (1210.01)

x=34.785198

.:. x is equalled to 34.78km

 

[G0ld3n_Sk1llz]

tthanks

pm me if u want any help with rs