Anyone want to help me with some trig?
2sec(squared) x - 3 + tanx = 0
Use your Trig Identities:
sec²x = 1 + tan²x
Therefore, you have:
2(1 + tan²x) - 3 + tanx = 0
2 + 2tan²x - 3 + tanx = 0
2tan²x + tanx - 1 = 0
^ Notice something? ^
Factor it. =D
(2tan - 1)(tan + 1)
^ Set both above equal to "0" ^
2tan - 1 = 0
2tan = 1
tan = 1/2
tan + 1 = 0
tan = -1
So, now you have (tan = 1/2) and (tan = -1)
Using a Unit Circle, find where Tangent is equal to 1/2 and -1. Or, use Tan Inverse of the numbers.
For (tan = 1/2), you will get 116.565 and 296.525, for Tangent is negative in Quadrants 2 and 4.
For (tan = -1), you will get 135 and 135, for Tangent is negative in Quadrants 2 and 4.
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If these are supposed to be in Quadrants 1 and 3, where Tangent is positive, I would be confused. Nevertheless, there you are Datsyuk4242, and good luck on your upcoming Tests / Quizzes as well!