[Source]Random Password Generator[Source]

Jimmy · Aug 20, 2009

Not too active here. Little thing I made in a few minutes to generate peudo-random passwords. Enjoy.

Code:

import java.util.*;
import java.security.*;

class PasswordGenerator {

    public static String alph = "abcdefghijklmnopqrstuvwxyz";

    public static void main(String[] args) {
	if(args.length == 2) {
		int length = 0;
		int times = 0;

		try {
			length = Integer.parseInt(args[0]);
			times = Integer.parseInt(args[1]);
		} catch (RuntimeException e) {
			System.out.println("Invalid args! Type 'java PasswordGenerator --help' for help");
		}

		for(int i1=0; i1<times; i1++) {
			SecureRandom random = new SecureRandom();
			StringBuilder builder = new StringBuilder();
			for(int i2=0; i2<length; i2++) {
				int rand = random.nextInt(2);
				switch(rand) {
					case 0:
						builder.append((random.nextInt(10)));
						break;
					case 1:
						builder.append(((random.nextInt(2) == 0) ? (Character.toString(alph.charAt(random.nextInt(24)))).toUpperCase().toCharArray()[0] : (Character.toString(alph.charAt(random.nextInt(24)))).toLowerCase().toCharArray()[0]));
						break;
				}
			}

			System.out.println("Password" + '[' + i1 + ']' + ": " + builder.toString());
		}
	} else if((args.length == 1) && args[0].equals("--help")) {
		System.out.println("Usage: java PasswordGenerator [length] [number]" + '\n' + 
			"	(Integer) length: The length each password should be" + '\n' +
			"	(Integer) number: The number of passwords to generate"
		);
	} else {
		System.out.println("Invalid args! Type 'java PasswordGenerator --help' for help");
	}
    }

}

NOTE: The way to use this should be obvious, but if it's not, the proper usage is 'java PasswordGenerator [length (The length your password should be)] [number (the number of passwords to generate)]'