Paper, Scissors, Rock -- Small problem, but still works

[Michael3455]

Here's my completed Paper, Scissors, Rock program. Written in c++ (Problem fixed, if a mod see's please delete last portion of the topic title). A big thanks has to go to Lnostdal from the ubuntuforums.org website as he helped fix my poorly implemented input checking code.

So, here it is!

#include <iostream>
#include <cstdlib> 
#include <ctime> 
using namespace std;

#define M_inline


template<typename T>
M_inline void readStdin(T& t, std::string msg, std::string on_wrong_input){
  std::cout << msg << std::flush;
  while(!(std::cin >> t)) {
    std::cout << on_wrong_input << std::flush;
    std::cin.clear();
    std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
    std::cout << msg << std::flush;
  }
}

int main()

{

	srand((unsigned)time(0)); 
 	int compchoice = ((rand()%3)+1); 
	int rock = 1;
	int paper = 2;
	int scissors = 3;	
	int i = 0;


		do{
    readStdin(i, "Enter 1 for Rock, 2 for Paper, 3 for Scissors: ",
                 "That wasn't a correct input. Try again!\n");
  } while((i < 1 || i > 3) && (cout << "Number not within range" << endl));



	switch (i){
	case 1:
		if (compchoice  == rock){
		cout<<"Rock doesn't beat rock, DRAW!\n"; 
			}
		else if (compchoice == paper){
		cout<<"Paper beats rocks, you loose!\n";
		}
		else{
		cout<<"Rock beats scissors, you win!\n";
		}
	break;
		
	
	

	case 2: 
		if (compchoice  == paper){
		 cout<<"Paper doesn't beat Paper, DRAW!\n "; 
			}
		else if (compchoice == rock){
		cout<<"Paper beats rocks, you WIN!\n";
		}
		else{
		cout<<"Scissors beats paper, you LOOSE!\n";
		}
		break;
	
	

	case 3:
		if (compchoice  == scissors){
		cout<<"Scissors doesn't beat scissors, DRAW!\n"; 
			}
		else if (compchoice == paper){
		cout<<"Scissors beats paper, you WIN!\n";
		}
		else{
		cout<<"Rock beats scissors, you LOOSE!\n";
		break;
		
	
	}

	
}
return 0;
cin.get();
}

 

[SidStudios]

Thanks! From your code I learnt how to use cin.get() in C++
Greatly appreciated!