Need calculus help

woot done

 

Requested Bump

 

Is it k(r^2)/3 or kr^(2/3) ?

 

for what? lemme screen shot the problem

 

thanks determinate, more where that came from

 

the answer would be option 3 m guessing, as h=k^2/3 and v=1/3*pie*r^squared*h, therefore
il put it all in brackets to make it less confusing
it comes to V=(1/3)*(pie)*(r^squared)*(k^(2/3))
as u can see that r has a power of 2 and k has a power of 2/3 and therefore to make the power of r into fraction aswell it would go like this 2=6/3 as these to r da same things.

therefore (6/3)+(2/3)=(8/) thus giving the answer V=(1/3)*pie*k*r^8/3
hope it helps

 

are you fairly certain in that answer?

 

yes i guess i am, as looking at the given answers i do not see that they have deferentiate or intergrated anything, and thus only using algebra that answer should be right

 

What butt licker says makes sense.

Since the answers still contain r, it seems they want you to simply leave it in terms of r.

 

ok thanks, and this one?

same setup as the first one

 

3.6 years
just scratch the (1/3)*Pi*k, solve the right side (will be about 37.4)
then test the 4 values on the left side.

 

need more help xD

 

3rd one, 7.8982223*1.4906748^x.

I just used a regression tool, lol.

 

thanks, and this one?



sorry i'm doing a 30 questions project for my calculus class and the ones im posting i couldn't figure out (got like 4 more)

 

I would say 3rd one because 17550000*.95^10 equals exactly that.

 

that question was answered already but thanks

 

that aint calc thats physics

 

Calculating the cost decrease in corporate jets over time really doesn't sound like physics >_>

 

I can help add my msn: [email protected]

 

its basic integration and the solution is correct btw