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Logarithms

Discussion in 'Homework Help' started by MohtasaUnique, Jan 23, 2011.

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  1. MohtasaUnique

    MohtasaUnique Grand Master
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    Logarithms
    How do you solve these: log(2x-1) = 2+log(x-2)
     
    MohtasaUnique, Jan 23, 2011
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  2. Koot

    Koot Forum Addict

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    Logarithms
    Subtract the logs to one side and using the log rules, you can combine them.

    log A - log B = log A/B

    The you can change the logs to 10^ and solve.
     
    Koot, Jan 23, 2011
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  3. panzerjager

    panzerjager Member

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    Logarithms

    Yea so : log(2x-1) = 2+log(x-2)
    becomes log(2x-1)-log(x-2)= 2
    which is: log[(2x-1)/(x-2)] = 2
    Turns into: 10^2 = (2x-1)/(x-2) = 100

    i dont have a calculator on me but its gonna be a relatively small #
     
    panzerjager, Feb 6, 2011
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  4. shelnaz2

    shelnaz2 Active Member
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    Logarithms
    dude is it natural log or log base 10?
     
    shelnaz2, Feb 10, 2011
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  5. valvemasher21

    valvemasher21 Active Member

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    Logarithms
    Subtract the log(x-2) to the other side, use the log identity to combine them(log A-log B=log(A/B), and raise 10 to the power of the other side and set it equal to (2x-1)/(x+2).
     
    valvemasher21, Feb 13, 2011
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