Geometry Homework Help!

Discussion in 'Homework Help' started by fly493, Apr 12, 2011.

Geometry Homework Help!
  1. Unread #1 - Apr 12, 2011 at 9:15 PM
  2. fly493
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    fly493 Active Member

    Geometry Homework Help!

    Prove:An altitude of an acute scalene triangle cannot bisect the angle from whose vertex it is drawn.

    There was no image given. This is an indirect proof. You would know what this is if you have done geometry.
    You can use this setup.

    __________Statements__________l______________Reasons_____________
    1)---------------------------------1)----------------------------------
     
  3. Unread #2 - Apr 14, 2011 at 11:11 PM
  4. General_Kerr
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    General_Kerr Active Member
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    Geometry Homework Help!

    The triangle is scalene, not isosceles. - Given
    In a Scalene triangle no angles or sides are the same. - Def scalene
    An Altitude is always perpendicular to the base. - Def Altitude
    A line drawn from a vertex that bisects the angle of the two sides can not be perpendicular because... uhrm...

    My math deals with physical objects and im used to assigning number to stuff.

    ok, lets take a triangle, knows Scalene.

    Vertices A, B, and C
    ^Hah firefawx doesn't have this word in its dictionary.

    It Is given that thse three angles can not be equal

    A != B
    B != C
    C != A
    Given

    Construct a line from Vertex B Perpendicular to line AC, name the new vertex D
    Angle ADB = Angle CDB = 90 Degrees
    - Constructed

    Now,
    (Im implying the angle symbol here)

    The two angles created by The drawn altitude
    ABD = 180 - (ADB + BAC)
    CBD = 180 - (CDB + BCA)

    Now, we know that ADB and CDB are both equal to 90 degrees
    So, we can subtract them.

    ABD = 90 - BAC
    CBD = 90 - BCA

    So, since we are given (Scalene) that BAC != BCA
    90 - BAC != 90 - BCA
    For the altitude to have "Bisected" the angle the two created angles must be equal, but since (as I just showed) While BAC != BCA ABD CAN NOT EQUAL CBD

    So, there's an algebratic proof that the two created angles can not be equal. (Thus they cant bisect)


    Ok here's all of my gobblygook removed
    Code:
    
    BAC != ABC
    CBA != ACB
    ACB != BAC
    
    Given, Definition of a scalene triangle.
    
    
    Line BD is an altitude Perpendicular to AC
     ADB =  CDB = 90 Degrees
    
    Definition Altitude/Construction
    
    
    ABD = 180 - (ADB + BAC)
    CBD = 180 - (CDB + BCA)
    
    A triangle must be 180 degrees
    
    
    (Algebraically Simplified, using known angles)
    90 - BAC
    90 - BCA
    
    Simplified
    
    
    90 - BAC   !=   90 - BCA
    (Note: This is because BAC and BCA are given as NOT EQUAL)
    Thus
    ABD != CBD
    
    For the angle to bisect ABD must = CBD
    But it can't! Thus
    
    BD Does not bisect ABC Because the created angles are not equal.
    
    Def. Bisect
    
    
    Not knowing your math teacher I dont know how he/she wants these explained, but there is my proof i just made up. :s
     
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