Factorise by extraction [MATHEMATICS] REWARD

[The Black Gamer]

(i) 2bc + 4ab
(ii) 6x2y + 3xy
(iii) ax + ay – az
(iv) 2x2 + 4y + 8zx
(v) ax – ay + bx – by
(vi) 2ax + 6ay + 3bx + 3by


Anybody want to help out?

I'll invite you to a 2M drop party

[email protected]

 

[Trackster]

Invite us to a drop party? So we are not guaranteed the money if we do this for you?

 

[The Black Gamer]

Need these completed VERY SOON

 

[AlaskaEgypt]

Try www.wolframalpha.com for all related math questions.

It gives you answers plus explanations and steps if need be.
Hope that helps, bud.

 

[iWoodKart]

Most of these are very similar, if you can do one you should be able to do the others..ill do 1 of them

i)2bc+4ab

we have common factor of 2 and b
2b(c+2a)

 

[HellBlitZ]

(v) ax – ay + bx – by

a (x-y) + b (x-y)
= (a+b)(x-y)

 

[DOUBLES50NOWoC0M]

(i) 2bc + 4ab
2b(c+2a)

(ii) 6x2y + 3xy
3xy(4+1) --> 3xy(5) --> 15xy

(iii) ax + ay – az
a(x+y-z)

(iv) 2x2 + 4y + 8zx
4x(1+2z) +4y --- > 4[x(1+2z) + y]

(v) ax – ay + bx – by
a(x-y) + b(x-y) ---> (a+b)(x-y)

(vi) 2ax + 6ay + 3bx + 3by
2a(x+3y) +3b(x+y)

Oh and btw you can't offer payment for hw help