Chemistry help please

[il0vec0llege]

I know I need to know how to do this but i was sick for a few days and i'm far behind.


Write word and balanced chemical equations for each of these chemical reactions.


1.Solid copper metal reacts with aqueous silver nitrate to produce silver metal and aqueous copper (II).

4 SOlid calcium metal reacts with water to form aqueious calcium hydroxide and hydrogen gas.

6. Solid potassium chlorate decomposes to form solid potassium chloride and oxygen gas.


Like i said i'm really grateful for any help possible.

 

[Koot]

First write out the compounds or elements on the left side and see what kind of reaction it goes through.

Synthesis, decomposition, single or double replacement.

Syn is A + B => C
Decmp C => A + B
Single AB + C => AC + B
Double AB + CD => AD + BC

Once you get the equation down, put down coefficients to balance.


You can ask if you don't understand a more specific part.

 

[oblivion9032]

Also remember that when you write the equations, the diatomic elements (H, N, O, F, Cl, I, and Br) need to have a subscript 2 when they are by themselves like this:

H[SUB]2[/SUB]

So thats how you would write your hydrogen and oxygen gas.

 

[il0vec0llege]

Ok nevermind i don't get this lol oh well

 

[Derosion]

I know I need to know how to do this but i was sick for a few days and i'm far behind.


Write word and balanced chemical equations for each of these chemical reactions.


1.Solid copper metal reacts with aqueous silver nitrate to produce silver metal and aqueous copper (II).

4 SOlid calcium metal reacts with water to form aqueious calcium hydroxide and hydrogen gas.

6. Solid potassium chlorate decomposes to form solid potassium chloride and oxygen gas.


Like i said i'm really grateful for any help possible.

Okay, these are fairly simple.

You have states, solid, liquid, gas and acid.
These states are put into brackets beside the word.
For the first one, it goes as,

Copper metal (s) + Silver nitrate (aq) ------ > Silver metal (s) + Copper (aq)
That's how you would write it out. The right side is the products and the left side is the reactants.

The states are put into brackets, (s) = solid, (aq) = acid
Look at the wording and how it is used and you'll pick up on it fairly quickly.

The other two go as so,
Sodium Calcium Metal (s) + Water (l) --- > Calcium Hydroxide (aq) + Hydrogen (g)

Those are word equations, as for balancing it's a bit more tricky.
You'd need to figure out the element symbol.

Ex: Calcium Hydroxide = CaOH

One of have the formula, you need to balance the amount of atoms.
An unbalanced equation:

H20 + CO2 --- > CH + O

There are 3 atoms of Hydrogen, 3 atoms Oxyen and one atom of Carbon on the left side. The hydrogen atoms are in H20 and the Oxygen atoms are from CO2 and one from H20. You see, the subscript shows the amount of atoms the element has. Balancing is balancing out the atoms of the equation.

Balanced equation of that:

H20 + 2CO2 --- > 2CH + 40

As you can see, I added numbers in front of the elements so it is balanced out.
2 multiplied by the CO2 will give me two atoms of Carbon and four atoms of Oxyen.

One the right side, I balanced a 2 to the CH and 4 to the O to balance it out.
That is a pretty minor example. I'm pretty sure you can get practice for your teacher, textbook or any other resource.

Good luck!

 

[Koot]

One of have the formula, you need to balance the amount of atoms.
An unbalanced equation:

H20 + CO2 --- > CH + O

There are 3 atoms of Hydrogen, 3 atoms Oxyen and one atom of Carbon on the left side. The hydrogen atoms are in H20 and the Oxygen atoms are from CO2 and one from H20. You see, the subscript shows the amount of atoms the element has. Balancing is balancing out the atoms of the equation.

Balanced equation of that:

H20 + 2CO2 --- > 2CH + 40

As you can see, I added numbers in front of the elements so it is balanced out.
2 multiplied by the CO2 will give me two atoms of Carbon and four atoms of Oxyen.

One the right side, I balanced a 2 to the CH and 4 to the O to balance it out.
That is a pretty minor example. I'm pretty sure you can get practice for your teacher, textbook or any other resource.

Good luck!

This is a terrible example, there is so many flaws with it. First off, CH and O cannot exist. Secondly, even if you were just demonstrating a point about balancing disregarding if it is even an equation in the first place you did it wrong. You completely neglected the oxygen in the water molecule. When you have a wrong equation, most times you can't possibly balance it.

Here's an example

CuSO4 + NaNO3 - > Cu(NO3)2 + Na2SO4 (Disregard if this actually takes place as I don't quite remember the solubility of em)

This is the balanced one (pretty simple example)

CuSO4 + 2NaNO3 - > Cu(NO3)2 + Na2SO4

 

[il0vec0llege]

Ok thanks guys this really helped close please.