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Anti scammed Osrsgod[NEED MOD HELP]

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I need help finding the victims, i know there was more than one victim but i can't find all of them.

I know this victim in particular was scammed 70M 07 or so.

http://www.sythe.org/report-scammer-archive/1929116-osrsgod-scammed-me.html

and another was scammed 35M but didn't have sufficient proof that osrsgod owned the skype firez.ommsythe which is proved in the link that he indeed does own that skype.

him and i agreed on $120 back for the maxed main, and the amount he scammed is the same amount.

So instead of me paying $120 for the account, i will be giving it to the people who were scammed.
Mod's please assist me in this, it would be greatly appreciated.

PS: I believe the second victim was around january 28-29th and had something in the title labeled "scammed 35m"


EDIT: http://www.sythe.org/report-scammer-archive/1923885-i-just-got-scammed-35-5m-member-site.html

It was this report where 35.5M was also scammed by the same skype.

I contacted the user scammed and asked him to remake his report so it is valid and i can repay him.
 
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According to Osrsgod, you've already committed the counter scam? You should always get moderator approval before a counter scam.
 
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Haven't been able to find any other victims from my look. Know that you can only refund the amount they were scammed and any excess must be given back to osrsgod.
 
if anything im short the money they're owed. so how should i do it?

$120 @ if i can possibly find gold for 1.25-1.35/m when gold at websites is 1.42/m+ so, do i give 65m and 30m? and call it a day?
if i can find gold for 1.25/m i can get 96m and the amount scammed was in excess of that.. so there is no "left over"
 
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The fairest way at least in my opinion would be dividing it up proportionally to what they were scammed.

For example if you received 95m from the purchase, 95/105.5 x 70 = 63 (rounded) and 95/105.5 x 35.5 = 32 (rounded). Then 63m (rounded) would go to user A, 32m would go to user B.
 
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