Free homework help here

Discussion in 'Archives' started by MatthewGor123, Oct 25, 2008.

Free homework help here
  1. Unread #21 - Oct 26, 2008 at 5:08 PM
  2. Daily
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    Stickied.
     
  3. Unread #22 - Oct 26, 2008 at 6:04 PM
  4. MatthewGor123
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    Thank ya.

    Obviously (well, except 1^∞, ∞^0, 1/∞, but whatever)...but we're not talking about starting with infinity...Obviously, if you want to end up with infinity any moron could figure out that ∞ + 0, or 1 * ∞ is equal to infinity. What I *meant* to say was that without defining ∞ as a symbol, it is impossible to end up with infinity through the basic operations without stating a progression.

    I'm sorry I couldn't guide you closer to the answer, because I personally don't know calculus that well yet (I think I'm going to study it independently this year). I'm glad I could help at least a little :D What class is this for? College level differential calculus?
     
  5. Unread #23 - Oct 26, 2008 at 6:12 PM
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    I'm doing further maths at my college and it was from the differential equations chapter.

    Youtube is quite good if you want to study some maths independently, there are a bunch of videos up on pretty advanced concepts.
     
  7. Unread #24 - Oct 26, 2008 at 6:20 PM
  8. MatthewGor123
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    Thanks for the tip! I would have never even considered YouTube as a very educational tool (like unless you want to learn how to do random things, like solve a Rubik's cube or some magic trick) but it does, in fact, have some pretty interesting stuff.

    Now all I need is a few more questions :O
     
  9. Unread #25 - Oct 26, 2008 at 9:33 PM
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    Alright, I guess I got unstickied. Oh well :p C'mon people, surely you must have SOME homework questions! I'm willing to answer them for any subject -> I have nothing better to do...
     
  11. Unread #26 - Oct 27, 2008 at 5:54 PM
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    Darn, no new posts. I'm still willing to help :p For free!
     
  13. Unread #27 - Oct 27, 2008 at 7:40 PM
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    Stay here for 9 weeks please
    Next quarter I'm going to take Pre-Cal
    Plz & TY
     
  15. Unread #28 - Oct 27, 2008 at 7:54 PM
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    I'm not going anywhere :p [assuming I don't get banned or something]. Ty for the post, anyways ^_^
     
  17. Unread #29 - Oct 29, 2008 at 8:01 PM
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    Okay, I need to find a reputable website that proves that blacks say the n-word more than non-blacks. Can you help?
     
  19. Unread #30 - Oct 29, 2008 at 8:53 PM
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  21. Unread #31 - Oct 29, 2008 at 9:24 PM
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    Hey im a freshman, not real good at math just trying to keep up my 3.0 GPA, In my middle school we use to only use decimals, and they just automatically switched us to fractions, think you could PM, or post here a mini-guide on them, because i really need to get it quick, my teacher is senial, and has no idea how to teach.
     
  23. Unread #32 - Oct 29, 2008 at 9:30 PM
  24. MatthewGor123
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    Alright; sure. Are you asking how to convert decimals to fractions? Or like how to add/subtract/multiply them? What specifically do you want to know?
     
  25. Unread #33 - Oct 29, 2008 at 9:32 PM
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    Just add subtract multiply divide, i have converting down pretty much.
     
  27. Unread #34 - Oct 29, 2008 at 10:33 PM
  28. MatthewGor123
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    Alright;

    ADDING FRACTIONS:
    Let's say you want to add 3/8 and 9/14.

    First thing you want to do is find the least common multiple of the denominators (the LCD). To find the LCD, unless you clearly recognize it, you write out the denominators in their prime factorization; 8 = 2 * 2 * 2, 14 = 2 * 7. Then, to find the LCD, you count the number of different prime factors each number has, and the LARGEST number of times each prime factor appears per number. If that made sense;
    8 = 2^3
    14 = 2^1 * 7^1.

    Therefore, you need 3 2's and 1 7 to be factors of the LCD. Therefore, your LCD will be 2^3 * 7^1 = 56.

    Now that you have your LCD, you have to manipulate your fractions so that the denominators of both are the same. So, for 3/8, you need to get 56 in the denominator (and we know it's a multiple of 8, as we just showed). Therefore, you can divide 56 by 8 to find how many times 8 goes into it. The answer is 7, so therefore, you rewrite 3/8 as (3*7)/(8*7) = 21/56.

    Next, you do the same thing for 9/14. 56/14 = 4, so (9*4)/(14*4) = 36/56.

    Next, you add 21/56 + 36/56. You add JUST the numerators, keeping the DENOMINATOR the same. (21 + 36) / 56 = 57/56. If you want, you can rewrite this as a mixed number; 1 and 1/56. Although it may seem quite confusing at first, it gets MUCH easier with practice.
    ~~~~~~~~~~~~~~~~~
    SUBTRACTING Fractions

    Let's say we wanna do 17/60 - 5/126.
    Remember the first step? We have to find the LCD.
    So;
    60 = 2^2 * 3 * 5
    126 = 2 * 3^2 * 7.

    So, we add up the HIGHEST number of each prime factor in the denominators; we need two 2's, two 3's, a 5, and a 7 to make up the LCD. So, the LCD = 4 * 9 * 5 * 7 = 1260 (yikes).

    But, we must solve the problem! 1260/60 = 21. 1260/126 = 10.
    So; we have (17*21)/1260 - (10*5)/1260.
    357/1260 - 50/1260 = 307/1260.
    ~~~~~~~~~~~~~~~~~~~~
    MULTIPLYING Fractions

    Luckily, here is where it gets easy :)

    Let's say you want to multiply

    3/4 * 8/11 * 33/21.

    Generally, you want to cancel stuff (meaning divide by n/n, yielding 1) before you do the multiplication, but it doesn't really matter. I'd like to do that first. So, this expression can be rewritten as 8/4 * 33/11 * 3/21 (you still have 3 * 8 * 33 in the numerator and 4 * 11 * 21 in the denominator). So, you can rewrite this as 2 * 3 * 1/7 (since we know that 8/4 = 2 and 33/11 = 3). Therefore, the answer is 6/7.

    However, a more straightforward way that leads you straight to the answer, then requires simplification, is just multiply the numerators and multiply the denominators. Literally. It's really simple. So, you have;
    (3 * 8 * 33)/(4 * 11 * 21) = 792 / 924. Next, you want to simplify this. If you don't happen to know that both are divisible by 132, you can keep dividing by simple factors that go into both, i.e; 4 (198/231), then 3 (66/77), then 11 (6/7) and you'll end up with the same answer.

    Quite simple really, once you get used to it.
    ~~~~~~~~~~~~~~~~
    Let's say you want to divide 3/7 by 2/5.
    So, you have (3/7) / (2/5).
    First step is to flip the division sign to a multiplication sign, and find the reciprocal of the fraction on the RIGHT (the divisor). So, you'd have:
    (3/7) * (5/2).
    Then, you do your multiplication (which you just reviewed), and get 15/14, or 1 1/14.

    Voila!



    Basically, all it comes down to is practice, practice, and more practice. Hope this helped!
     
  29. Unread #35 - Oct 30, 2008 at 3:40 PM
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    Im stuck on this problem help

    We are given unlimited number of identical, very thin dominoes. The length of a domino is 2 cm and it's mass is neglegable (10 ^ -4314 gram per domino).
    Suppose we stack them(assume we are infinitely powerful), one on top of the other, so that the stack advances horizontally in one direction because each is offset a little. the top domino is offset 1cm, and as we move down the stack they are offset progressively less from each other so as to keep the center of gravity. the stack is kept stable only by gravity.
    1) show that the stack can advance infinite distance. HINT: numerate the dominoes in a stack from the top. Note that a stack of two dominoes can advance 1cm since the center of the first domino should be above the edge of the second domino. Place the third domino underneath the first two dominoes so that the edge of the third domino is below the center of the stack of the two dominoes that has been built already.
     
  31. Unread #36 - Oct 30, 2008 at 4:27 PM
  32. Evon
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    MatthewGor123, I just wanted to let you know, you are the man. (not trying to spam or anything, I'm sure I'll have some question to ask you in the near future. I just wanted to say thanks for your will to help.)
     
  33. Unread #37 - Oct 30, 2008 at 7:27 PM
  34. MatthewGor123
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    It seems pretty clear to me that it this is a calculus problem, and a difficult one at that, and it will involve a numeric progression - I'll try to think of what it may be, when I get a chance.

    EDIT: I just did a quick web search regarding stacks with center of mass, and guess what I found! Somebody with the same exact problem as you! :) http://answers.yahoo.com/question/index?qid=20061026223155AAXBOKn

    That should explain it much better than I can, as the guy obviously knows his calculus better than I do.

    If that wasn't sarcastic, then I really appreciate it :) I look forward to trying my best to help :p
     
  35. Unread #38 - Nov 1, 2008 at 6:19 PM
  36. Datsyuk4242
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    Hmmm, just wondering if anyone could help me work out a little math problem. I calculated an answer that was ultimately different than what the textbook had, so it'd be great if I got a second opinion.


    The members of a high school bastketball team are driving from Calgary to Vancouver, which is a distance of 675km. Each tire on their van has a radius of 32 cm. If the team members drive at a constant speed and cover the distance from Calgary to Vancouver in 6 H 45 min, what is the angular velocity, in radians/sec, of each tire during the drive?


    Please and thank you :)
     
  37. Unread #39 - Nov 1, 2008 at 6:39 PM
  38. Evon
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    Nah man, wasn't sarcastic.
     
  39. Unread #40 - Nov 1, 2008 at 6:41 PM
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    I think you would take 32cm as your radian measure and then divide that by 6 h and 45mins converted to secs. This should give you rads/sec
     
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