echo in C

Code:

#include <stdio.h> 
int main(int argc, char *argv[]) {
  int i;
  for(i=1;i<argc;i++) {
    printf("%s",&argv[i][0]);
    if(!(i+1==argc)) {
      printf(" ");
    }
  }
  printf("\n");
}

Written by me and Fouisgras over MSN :3

Can take an arbitrary number of arguments, but doesn't die on 0 args (Just prints newline, which is sad). Any help on detecting a 0 number of arguments would be much appreciated.

 

:3 horray.

 

So it practically just prints out the command line arguments?

 

Code:

#include <stdio.h> 
#include <ctype.h>
int main(int argc, char *argv[]) {
  int i;
  if(argv[1]!=NULL) { // If there are arguments
    for(i=1;i<argc;i++) {
      printf("%s ",&argv[i][0]); // Loop through the arguments printing them
    }
  }
  else { // If no arguments
    for(i=0;i<sizeof(argv[0]);i++) {
      argv[0][i] = toupper(argv[0][i]); // Take the [0] argument which will be the name of the command and make it uppercase
    }
    printf("%s is on.\n", argv[0]); // Print out "<name of command> is on" just as echo does when there are no arguments
  }
}

Made a couple minor changes and added detection for zero arguments like the real 'echo' has. Also, commented it but I think that's mostly to help out Fouis.

 

Thanks null

 

UNIX and Windows both already have an echo command... >_>

 

Yet inefficient. Ours is smaller. Less bloated is always win.

Anyway it wasn't meant to be fully function. It was mainly an excercise.

GTFO

 

We know :3 But ours is small and sexy, and the GNU one is massive.