Algebra Help

Discussion in 'Archives' started by hitmanchimp6, Feb 21, 2008.

Algebra Help
  1. Unread #1 - Feb 21, 2008 at 8:04 PM
  2. hitmanchimp6
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    Algebra Help

    THIS IS FREE! NOT limited to Algebra.

    If anyone here needs help with Algebra, or some other math, I may be able to help. I can only go up to 10th grade math though, which is Algebra 2.
    I may also be able to help with other subjects(i.e. history, science, physics)

    I WILL NOT do your homework for you. I will, however give you answers to the best of my ability, or memory(whichever takes me further).

    Just remember: If you are just looking for answers, and not how to solve the problem, you will be in trouble on the tests. So if you need help understanding anything, please ask. I can't promise a right answer, but I can try.
     
  3. Unread #2 - Feb 21, 2008 at 8:27 PM
  4. Shredderbeam
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    Algebra Help

    x^2 = 144. What is x?
     
  5. Unread #3 - Feb 21, 2008 at 8:29 PM
  6. Viny
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    Viny I'd tell you but...
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    Algebra Help

    Zomg?!?! I think it's something like 12. I may be wrong.
     
  7. Unread #4 - Feb 21, 2008 at 8:36 PM
  8. 1337_Byte
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    Algebra Help

    -12 and 12
     
  9. Unread #5 - Feb 21, 2008 at 8:36 PM
  10. hitmanchimp6
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    Algebra Help

    good joke. 12
     
  11. Unread #6 - Feb 21, 2008 at 8:37 PM
  12. Shredderbeam
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    Algebra Help

    It was a test. You forgot -12. :(
     
  13. Unread #7 - Feb 21, 2008 at 8:39 PM
  14. Viny
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    Viny I'd tell you but...
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    Algebra Help

    As did I, lol.
     
  15. Unread #8 - Feb 21, 2008 at 8:40 PM
  16. AKASNM
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    Algebra Help

    ANy Algebra? Try this one.


    (2^2 6^7 )^8
    (---------)
    (7^3____)


    It's a fraction, solve it.
     
  17. Unread #9 - Feb 21, 2008 at 8:44 PM
  18. hitmanchimp6
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    Algebra Help

    I said up to 10th grade if you read the first post... Can't give an answer that won't look ridiculous, tbh.
     
  19. Unread #10 - Feb 21, 2008 at 8:53 PM
  20. AKASNM
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    Algebra Help

    Ok,here.

    2x+90=5x+180


    Solve for X
     
  21. Unread #11 - Feb 21, 2008 at 8:58 PM
  22. Govind
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    Prove it! Trole Tier 1 Prizebox Tortoise Penis Le Monkey UWotM8? Wait, do you not have an Archer rank? Potamus

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    Algebra Help

    >_>
    All he'd have to do is graph it on a TI83 and look for the zeroes/intercepts. Not difficult.
     
  23. Unread #12 - Feb 21, 2008 at 9:00 PM
  24. Fouisgras
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    Algebra Help

    Try this.

    Use the fundamental identities to simply. Show all steps.

    (4cosx - 3sinx)^2 + (3cosx + 4sinx)^2

    hint: Expand then use the first pythagorean identity.
     
  25. Unread #13 - Feb 21, 2008 at 9:01 PM
  26. hitmanchimp6
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    Algebra Help

    X= -30
     
  27. Unread #14 - Feb 21, 2008 at 9:03 PM
  28. Fouisgras
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    Algebra Help

    Edit: oh damn he beat me to it haha.

    Anywhom... guna find mine hitman? lol.
     
  29. Unread #15 - Feb 21, 2008 at 9:03 PM
  30. hitmanchimp6
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    Algebra Help

    Leaving now. PM me if you are SERIOUS about help. Ty.
     
  31. Unread #16 - Feb 21, 2008 at 9:16 PM
  32. rsplayer95
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    Algebra Help

    Well I don't need much help in math , I am best at math, but if I may this is very simple: Write an equation of a line perpendicular to y=4/5x + 7. I made that one up as I went along so I don;t know the solution yet but I will do it in my head after I post this.
     
  33. Unread #17 - Feb 21, 2008 at 9:26 PM
  34. krayzkiller
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    Algebra Help

    so are you looking for vouches for this??? or are you just bored and a math geek and want to help people??
     
  35. Unread #18 - Feb 21, 2008 at 10:17 PM
  36. rs nechryeal
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    Algebra Help

    perpendicular would be y=4/5x-23

    EDIT: anything with the coefficient of x being 4/5 would be perpendicular to that line
     
  37. Unread #19 - Feb 21, 2008 at 10:36 PM
  38. Blurb
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    Algebra Help

    :) nice idea, if anyone needs help with up to Calc BC i can help :)
     
  39. Unread #20 - Feb 22, 2008 at 12:28 AM
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    Algebra Help

    Oh, how I love the TI83. And oh how i hate how we were not allowed to use them in precal and half of cal...

    Edit: We just started with limits and derivitives last week. The basic formula for figuring crap out is...
    [​IMG]

    Not to incredibly hard, just really tedious if you have a problem with a lot of foiling. Like the other day we had one with 34 "parts" (for lack of a better word) once it was expanded all the way thru foiling. Annoing trying to go back and find something if you messed up.
     
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