><need help with findcolorspiral><

when i try to use color spiral it always say's syntax error or something like that i think i got it down pat but i duno
this is wat i got
xs=x start xe= x end ys= y start ye= y end
is this right or wat? if anyone could plz help me i would realy appriciate it thx..

 

Show me one of your uses.

 

it should be like this:

Code:

FindColorSpiral(x,y,Color,XS,YS,XE,YE)

now x,y is cordinates it will store where it found the color(if it found else its 0,0)

xs,ys,xe,ye

imagine that its a box

like this:

the box is the rs client window.

-----------------|
|---|XS,YS.....|--|
|---|.............|--|
|---|.....XE,YE|--|
|----------------|

understand?

now it will search for the color inside the box (dotted box)


XS,YS,XE and YE is cordinates provided by you, with the color picker.

XS should be lower than XE
YS should be lower than YE
ELSE
you will get errors screaming!

hope u understood

 

Code:

program New;
var
x, y: Integer;
begin
FindColorSpiral(x,y,3234234,1,1,4,4)
end.

I get no errors.

 

thank you for your help now if inally get it lol now i can fisnish my script thank god